Difference between revisions of "Bit.bor"
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| + | {{lowercase}} | ||
| + | {{Function | ||
| + | |name=bit.bor | ||
| + | |args={{Type|number}} m, {{Type|number}} n | ||
| + | |api=bit | ||
| + | |returns={{Type|number}} the value of <var>m</var> OR <var>n</var> | ||
| + | |addon=ComputerCraft | ||
| + | |desc=Computes the bitwise inclusive OR of two numbers | ||
| + | |examples= | ||
| + | {{Example | ||
| + | |desc=OR the number 18 (10010) with the number 3 (00011), yielding 19 (10011) | ||
| + | |code=print(bit.bor(18, 3)) | ||
| + | |output=19 | ||
| + | }} | ||
| + | }} | ||
== Explanation == | == Explanation == | ||
| − | All bit operations operate in | + | All bit operations operate in binary numeral system [http://en.wikipedia.org/wiki/Binary_numeral_system]. An inclusive OR operation between two bits yields a 1 if either of the bits is 1 and a 0 if they are both 0. This function produces an output by computing the OR of each bit of its two inputs independently. So, for the example above: |
| − | + | {| class="wikitable" | |
| − | - | + | |- |
| − | + | ! Bit index: | |
| − | + | | 4 | |
| − | + | | 3 | |
| − | + | | 2 | |
| − | + | | 1 | |
| − | + | | 0 | |
| − | + | |- | |
| − | + | ! Input 1 (18): | |
| − | + | | 1 | |
| − | + | | 0 | |
| + | | 0 | ||
| + | | 1 | ||
| + | | 0 | ||
| + | |- | ||
| + | ! Input 2 (3): | ||
| + | | 0 | ||
| + | | 0 | ||
| + | | 0 | ||
| + | | 1 | ||
| + | | 1 | ||
| + | |- | ||
| + | ! Calculation: | ||
| + | | 18 has a 1 | ||
| + | | Both 0 | ||
| + | | Both 0 | ||
| + | | Both 1 | ||
| + | | 3 has a 1 | ||
| + | |- | ||
| + | ! Output (19): | ||
| + | | 1 | ||
| + | | 0 | ||
| + | | 0 | ||
| + | | 1 | ||
| + | | 1 | ||
| + | |} | ||
| − | + | [[Category:API_Functions]] | |
Latest revision as of 01:34, 12 July 2013
 Function bit.bor | |
| Computes the bitwise inclusive OR of two numbers | |
| Syntax | bit.bor(number m, number n) |
| Returns | number the value of m OR n |
| Part of | ComputerCraft |
| API | bit |
Examples
 Example | |
| OR the number 18 (10010) with the number 3 (00011), yielding 19 (10011) | |
| Code |
print(bit.bor(18, 3)) |
| Output | 19 |
Explanation
All bit operations operate in binary numeral system [1]. An inclusive OR operation between two bits yields a 1 if either of the bits is 1 and a 0 if they are both 0. This function produces an output by computing the OR of each bit of its two inputs independently. So, for the example above:
| Bit index: | 4 | 3 | 2 | 1 | 0 |
|---|---|---|---|---|---|
| Input 1 (18): | 1 | 0 | 0 | 1 | 0 |
| Input 2 (3): | 0 | 0 | 0 | 1 | 1 |
| Calculation: | 18 has a 1 | Both 0 | Both 0 | Both 1 | 3 has a 1 |
| Output (19): | 1 | 0 | 0 | 1 | 1 |
