Difference between revisions of "Bit.bor"

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{{Function
 
{{Function
|name=bit.band
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|name=bit.bor
|args=[[int (type)|int]] m, [[int (type)|int]] n
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|args={{Type|number}} m, {{Type|number}} n
 
|api=bit
 
|api=bit
|returns=[[int]] the value of <var>m</var> OR <var>n</var>
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|returns={{Type|number}} the value of <var>m</var> OR <var>n</var>
 
|addon=ComputerCraft
 
|addon=ComputerCraft
 
|desc=Computes the bitwise inclusive OR of two numbers
 
|desc=Computes the bitwise inclusive OR of two numbers
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[[Category:API_Functions]]

Latest revision as of 01:34, 12 July 2013


Grid Redstone.png  Function bit.bor
Computes the bitwise inclusive OR of two numbers
Syntax bit.bor(number m, number n)
Returns number the value of m OR n
Part of ComputerCraft
API bit

Examples

Grid paper.png  Example
OR the number 18 (10010) with the number 3 (00011), yielding 19 (10011)
Code
print(bit.bor(18, 3))
Output 19


Explanation

All bit operations operate in binary numeral system [1]. An inclusive OR operation between two bits yields a 1 if either of the bits is 1 and a 0 if they are both 0. This function produces an output by computing the OR of each bit of its two inputs independently. So, for the example above:

Bit index: 4 3 2 1 0
Input 1 (18): 1 0 0 1 0
Input 2 (3): 0 0 0 1 1
Calculation: 18 has a 1 Both 0 Both 0 Both 1 3 has a 1
Output (19): 1 0 0 1 1