Difference between revisions of "Bit.bor"
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+ | {{lowercase}} | ||
+ | {{Function | ||
+ | |name=bit.band | ||
+ | |args=[[int (type)|int]] m, [[int (type)|int]] n | ||
+ | |api=bit | ||
+ | |returns=[[int]] the value of <var>m</var> OR <var>n</var> | ||
+ | |addon=ComputerCraft | ||
+ | |desc=Computes the bitwise inclusive OR of two numbers | ||
+ | |examples= | ||
+ | {{Example | ||
+ | |desc=OR the number 18 (10010) with the number 3 (00011), yielding 19 (10011) | ||
+ | |code=print(bit.bor(18, 3)) | ||
+ | |output=19 | ||
+ | }} | ||
+ | }} | ||
== Explanation == | == Explanation == | ||
− | All bit operations operate in | + | All bit operations operate in binary numeral system [http://en.wikipedia.org/wiki/Binary_numeral_system]. An inclusive OR operation between two bits yields a 1 if either of the bits is 1 and a 0 if they are both 0. This function produces an output by computing the OR of each bit of its two inputs independently. So, for the example above: |
− | + | {| class="wikitable" | |
− | - | + | |- |
− | + | ! Bit index: | |
− | + | | 4 | |
− | + | | 3 | |
− | + | | 2 | |
− | + | | 1 | |
− | + | | 0 | |
− | + | |- | |
− | + | ! Input 1 (18): | |
− | + | | 1 | |
− | + | | 0 | |
− | + | | 0 | |
− | + | | 1 | |
+ | | 0 | ||
+ | |- | ||
+ | ! Input 2 (3): | ||
+ | | 0 | ||
+ | | 0 | ||
+ | | 0 | ||
+ | | 1 | ||
+ | | 1 | ||
+ | |- | ||
+ | ! Calculation: | ||
+ | | 18 has a 1 | ||
+ | | Both 0 | ||
+ | | Both 0 | ||
+ | | Both 1 | ||
+ | | 3 has a 1 | ||
+ | |- | ||
+ | ! Output (19): | ||
+ | | 1 | ||
+ | | 0 | ||
+ | | 0 | ||
+ | | 1 | ||
+ | | 1 | ||
+ | |} |
Revision as of 22:56, 11 March 2012
Function bit.band | |
Computes the bitwise inclusive OR of two numbers | |
Syntax | bit.band(int m, int n) |
Returns | int the value of m OR n |
Part of | ComputerCraft |
API | bit |
Examples
Example | |
OR the number 18 (10010) with the number 3 (00011), yielding 19 (10011) | |
Code |
print(bit.bor(18, 3)) |
Output | 19 |
Explanation
All bit operations operate in binary numeral system [1]. An inclusive OR operation between two bits yields a 1 if either of the bits is 1 and a 0 if they are both 0. This function produces an output by computing the OR of each bit of its two inputs independently. So, for the example above:
Bit index: | 4 | 3 | 2 | 1 | 0 |
---|---|---|---|---|---|
Input 1 (18): | 1 | 0 | 0 | 1 | 0 |
Input 2 (3): | 0 | 0 | 0 | 1 | 1 |
Calculation: | 18 has a 1 | Both 0 | Both 0 | Both 1 | 3 has a 1 |
Output (19): | 1 | 0 | 0 | 1 | 1 |