Difference between revisions of "Bit.bxor"
From ComputerCraft Wiki
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m (Mapped "int" to "int (type)".) |
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|args=[[int (type)|int]] m, [[int (type)|int]] n | |args=[[int (type)|int]] m, [[int (type)|int]] n | ||
|api=bit | |api=bit | ||
| − | |returns=[[int]] the value of <var>m</var> XOR <var>n</var> | + | |returns=[[int (type)|int]] the value of <var>m</var> XOR <var>n</var> |
|addon=ComputerCraft | |addon=ComputerCraft | ||
|desc=Computes the bitwise exclusive OR of two numbers | |desc=Computes the bitwise exclusive OR of two numbers | ||
Revision as of 18:27, 30 November 2012
 Function bit.bxor | |
| Computes the bitwise exclusive OR of two numbers | |
| Syntax | bit.bxor(int m, int n) |
| Returns | int the value of m XOR n |
| Part of | ComputerCraft |
| API | bit |
Examples
 Example | |
| XOR the number 18 (10010) with the number 3 (00011), yielding 17 (10001) | |
| Code |
print(bit.bxor(18, 3)) |
| Output | 17 |
Explanation
All bit operations operate in binary numeral system [1]. An exclusive OR operation between two bits yields a 1 if the bits are unequal and a 0 if they are equal. This function produces an output by computing the XOR of each bit of its two inputs independently. So, for the example above:
| Bit index: | 4 | 3 | 2 | 1 | 0 |
|---|---|---|---|---|---|
| Input 1 (18): | 1 | 0 | 0 | 1 | 0 |
| Input 2 (3): | 0 | 0 | 0 | 1 | 1 |
| Calculation: | 1 ≠ 0 | 0 = 0 | 0 = 0 | 1 = 1 | 0 ≠ 1 |
| Output (17): | 1 | 0 | 0 | 0 | 1 |
